Answer:
StartFraction 16 over 81 EndFraction
Step-by-step explanation:
There are 4 prime numbers from 2 to 10 (2, 3, 5, 7) and 9 numbers from 2 - 10. Total possibilities: 9 * 9 = 81
Prime possibilities: 4 * 4 = 16
Therefore the answer is 16/81 or StartFraction 16 over 81 EndFraction
There are 55 multiples of 5 between 81 and 358
Answer:
3 I think.
Step-by-step explanation:
it's positive and it's also an absolute
Answer:
Answer is 225.
We have to find the sum of 15 terms of the series
sigma 1 to 15 (2n-1)
This can be split as per summation terms as
sigma 2n - sigma 1
sigma 2n can again be simplified by taking 2 outside
sigma 2n= 2 times sum of natural numbers of 1 to 15
= 2(15)(16)/2= 240
sigma 1= 1+1+...15 times= 15
Hence final answer is
= 2 times sigma n - (n) = 240-15 = 225.
Step-by-step explanation:
Answer:
60
Step-by-step explanation: