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3 years ago

9

The atmosphere is a solution ofMostly nitrogen with oxygen carbon dioxide and water vapor in small amounts the solvent and the s

olution is

1 answer:

KiRa [710]3 years ago

6 0

Answer:

Nitrogen; the atmosphere

Explanation:

The solvent is the fluid present in greatest amount — nitrogen.

The solution is the solvent plus all the solutes — the atmosphere.

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Picture of gas laws question below:

Vera_Pavlovna [14]

Volume of the tank is 5.5 litres.

Explanation:

mass of the CO2 is given 8.6 grams

Pressure of the gas is 89 Kilopascal which is 0.8762 atm

Temperature of the gas is 29 degrees ( 0 degrees +273.5= K) so (29+273)

R = gas constant 0.0821 liter atmosphere per kelvin)

FROM THE IDEAL GAS LAW

PV=nRT ( P Pressure, V Volume, n is number of moles of gas, R gas constant, Temperature in Kelvin)

no of moles = mass/atomic mass

= 8.6/44

= 0.195 moles

now putting the values in equation

V=nRT/P

= 0.195*0.0821*302/ 0.8762

= 5.5 litres.

As the carbon dioxide gas occupies the volume os the tank hence volume of tank is 5.5 litres.

4 0

3 years ago

Classify each process as either physical or a chemical change.

Dafna11 [192]

Answer:

I think they are all correct

7 0

3 years ago

As the population in a small town grows, a new water treatment plant is built. The plant is built on a local river where it can

xenn [34]

Answer:

A. Treated water from the plant would affect communities downriver.

Explanation:

7 0

3 years ago

Particals in the nucleus of an atom are its _________ and ____________.

Illusion [34]

That would be Protons and Neutrons.

6 0

3 years ago

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

<u>Answer:</u> The density of gold in $g/cm^3$ is $19.22g/cm^3$

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

6 0

3 years ago