See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer isthe hypotenuse is (3√2)/2
Volume of one cubic block = (1/6)^3 = 1/216 cu ins
Volume of the prism = 1/3 * 2/3 * 2/3 = 4/27 cu ins
Number of blocks to fill prism = 4/27 / 1/216 = (216*4) / 27 = 32
Answer:
Step-by-step explanation:
sin2x = 2sinx*cosx
=
* cosx
=
* cosx
= 2 
=
= 24/25
Connect the bdc letters together.
First you write what the vectors are, then you subtract z from w by subtracting their corresponding values <-4-3,1-4>= <-7,-3>, then to get subtracting the next answer you subtract w from z which is <3--4,4-1> = <7,3>