Ok, simple.
Carl has 4 less than triple the amount Toni has.
Toni has x amount of CDs.
Carl has 3x - 4 amount of CDs.
Hope this helps!
Answe
Given,
f(x) = 49 − x² from x = 1 to x = 7
n = 4

For x= 1
f(x₀) = 49 - 1^2 = 48
x = 2.5
f(x₁) = 42.75
x = 4
f(x₂) = 49 - 4^2 = 33
x = 5.5
f(x₃) = 49 - 5.5^2 = 18.75
x = 7
f(x₄) = 49 - 7^2 = 0
We have to evaluate the function on therigh hand point
![A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%2Bf%28x_4%29%5D)
![A = 1.5 [42.75+33+18.75+0]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B42.75%2B33%2B18.75%2B0%5D)

For Area for left hand sum
![A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_0%29%2Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%5D)
![A = 1.5 [48+42.75+33+18.75]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B48%2B42.75%2B33%2B18.75%5D)

Answer:
A
Step-by-step explanation:
given 2 secants drawn from an external point to the circle , then
the product of the measures of one secant's external part and that entire secant is equal to the product of the other secant's external part and that entire secant, that is
9(9 + 2 + 3x) = 10(10 + 2x + 2)
9(11 + 3x) = 10(12 + 2x) ← distribute parenthesis on both sides
99 + 27x = 120 + 20x ( subtract 20x from both sides )
99 + 7x = 120 ( subtract 99 from both sides )
7x = 21 ( divide both sides by 7 )
x = 3
Answer:
1.28
Step-by-step explanation:
x = 1.28