Answer:
The person who has the greatest spread is Jezebal because his range is 22 while Collin's range is 18.
Jezebal's range :
26 - 4 =22
Collin's range:
21 - 3 = 18
The person who has the least IQR is Collin
Jezebal :
4, 5, 8, 10, 11, 14, 20, 20, 26
Since there are nine values 11 is the median so the first quartile is 6.5 and the third quartile is 20. 20 - 6 = 14
Collin : 3, 9, 9, 14, 15, 16, 17, 20, 21
The median is 15, the first quartile is 9 and the third quartile is 18.5. 18.5 - 9 = 9.5
Jezebal has the greatest spread
Collin has the least IQR
Do you do K12 by any chance?
The slope is 3/2.
The y-intercept is 3.
Answer:
B) ![8\sqrt[4]{4}](https://tex.z-dn.net/?f=8%5Csqrt%5B4%5D%7B4%7D)
Step-by-step explanation:
![(2^{8} *2^{6} )^\frac{1}{4} = (2^{8+6} )^\frac{1}{4} =(2^{14} )^\frac{1}{4} =2^{\frac{7}{2} }=\sqrt{2^{7} } =2^{3} \sqrt{2} =8\sqrt{2} = 8\sqrt[4]{2^{2} } = 8\sqrt[4]{4}](https://tex.z-dn.net/?f=%282%5E%7B8%7D%20%2A2%5E%7B6%7D%20%29%5E%5Cfrac%7B1%7D%7B4%7D%20%3D%20%282%5E%7B8%2B6%7D%20%29%5E%5Cfrac%7B1%7D%7B4%7D%20%3D%282%5E%7B14%7D%20%29%5E%5Cfrac%7B1%7D%7B4%7D%20%3D2%5E%7B%5Cfrac%7B7%7D%7B2%7D%20%7D%3D%5Csqrt%7B2%5E%7B7%7D%20%7D%20%20%3D2%5E%7B3%7D%20%5Csqrt%7B2%7D%20%3D8%5Csqrt%7B2%7D%20%3D%208%5Csqrt%5B4%5D%7B2%5E%7B2%7D%20%7D%20%3D%208%5Csqrt%5B4%5D%7B4%7D)
Answer:
R=6.57978
also everyone add my sc- amber_hughes42
Step-by-step explanation:
we are given
I=3.8 \times 10^6
I_0=1
now, we can use formula
R=log(\frac{I}{I_0} )
now, we can plug these values
we get
R=log(\frac{3.8 \times 10^6}{1} )
