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3 years ago

Given: m∠A + m∠B = m∠B + m∠C Prove: m∠C = m∠A

Mathematics

2 answers:

mel-nik [20]3 years ago

8 0

Answer:

See below.

Step-by-step explanation:

m∠A + m∠B = m∠B + m∠C

Use the subtraction property of equality to subtract m<B from both sides of the equation.

m∠A + m∠B - m<B = m∠B - m<B + m∠C

m∠A = m∠C

kirill [66]3 years ago

3 0

Answer:

this is answer

you are welcome

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3 years ago

A water rocket is projected vertically upward from the ground. Its height (h) m above ground after t seconds is given by h= 20-5

saw5 [17]

Answer:

t=4 seconds

Step-by-step explanation:

The height of the water jacket that is projected vertically upward is given by the equation:

$h = 20 - 5(t - 2)^{2}$

We want to find the time that, the rocket reaches the ground.

When the rocket reaches the ground, the height , h becomes 0.

This implies that:

$20 - 5(t - 2)^{2} = 0$

Subtract 20 from both sides:

$- 5(t - 2)^{2} = - 20$

Divide through by -5;

${(t - 2)}^{2} = 4$

Take square root:

$(t - 2) = \pm \sqrt{4}$

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Therefore the feasible time is after 4 seconds.

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3 years ago