Answer:
Step-by-step explanation:
Question (1)
x² + 10x + 12
= x² + 2(5x) + 5² - 5² + 12
= [x² + 2(5x) + 5²] - 5² + 12
= (x + 5)² - 25 + 12 [Since, a² + 2ab + b² = (a + b)²]
= (x + 5)² - 13
Question (2)
y² - 6y - 15
= y² - 2(3y) - 15
= y² - 2(3y) + 3² - 3² - 15
= [y² - 2(3y) + 3²] - 3² - 15 [Since, a² - 2ab + b² = (a - b)²]
= (y - 3)² - 3²- 15
= (y - 3)² - 9 - 15
= (y - 3)² - 24
The dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.
<h3>What is the Pythagoras theorem?</h3>
The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.
We have:
Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The other end of the leash is tied to the top of an 8-foot pole.
After drawing a right-angle triangle from the above information.
Applying Pythagoras' theorem:
60² = 6² + x²
After solving:
x = 59.69 ≈ 59.7 foot
Thus, the dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.
Learn more about Pythagoras' theorem here:
brainly.com/question/21511305
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Answer:
Step-by-step explanation:
Left Hand Side
Change to sin(theta) and cos(theta)
csc(theta) = 1/sin(theta)
cot(theta) = cos(theta)/sin(theta)
1/sin(theta) - cos(theta)/sin(theta) Put over Sin(theta) Common denominator
[1 - cos(theta)] / sin(theta) Multiply numerator and denominator by 1 + cos(theta)
(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))
(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)
sin^2(theta) / (sin(theta)* ( 1 + cos(theta)
sin(theta) / (1 + cos(theta) )
Right hand Side.
See Above.
Answer:21
Step-by-step explanation:
Find the median. Separate everything above the median into two groups. Take the group with the larger numbers we’ll call this the upper quartile. Find the median of the larger group or upper quartile. Take the group with the smaller numbers, which we’ll call the lower quartile. Find the median of the smaller group or lower quartile. Subtract the median of the lower quartile from the median of the upper quartile and you will find the inner quartile range. In this case, it is 21
