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Snowcat [4.5K]
3 years ago
10

How are rates and ratios similar?

Mathematics
2 answers:
Elza [17]3 years ago
6 0
A rate<span> is a </span>ratio<span> between two quantities of </span>different<span> units, likes miles and hours, or dollars and gallons.</span>
Alona [7]3 years ago
3 0
Um correction A rate is a little bit different than the ratio, it is a special ratio. It is a comparison of measurements that have different units 
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Is -7 + 9 equals -9 + 7 true false or open
jeka57 [31]

False because the answer to the problems are different. One is positive and one is negative.

7 0
4 years ago
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If P(A)=0.6, P(B)=0.3, and P(A and B)=0.18, find P(A or B).
Marianna [84]

Answer:

The value of P(AUB) = 0.72

Step-by-step explanation:

As

  • P(A) = 0.6
  • P(B) = 0.3
  • P(A∩B) = 0.18

We can determine the value of P(A∩B) Using the formula

P(AUB) = P(A) + P(B) - P(A∩B)

            = 0.6 + 0.3 - 0.18

             = 0.72

Therefore, the value of P(AUB) = 0.72

3 0
4 years ago
Plz help I will give Brianly
Andreyy89

Answer:

the answer is 89

Step-by-step explanation:

this is a hard one to salve but basically if you know and lern hout to do it it is not that hard

4 0
3 years ago
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Please help ASAP!!!!!!!!!! Which expression is equivalent to the following complex fraction? 1 + StartFraction 1 Over y EndFract
sveticcg [70]

Answer:

(B)\dfrac{y+1}{y-1}

Step-by-step explanation:

We are to find an equivalent expression for:

\dfrac{1+\frac{1}{y} }{1-\frac{1}{y}}

Step 1: Combine the terms in the numerator into one fraction. Do the same for the denominator.

=\dfrac{\frac{y+1}{y} }{\frac{y-1}{y}}

Step 2: Write on a straight line and simplify

=\dfrac{y+1}{y} \div \dfrac{y-1}{y}\\=\dfrac{y+1}{y} \times \dfrac{y}{y-1}\\=\dfrac{y+1}{y-1}

The correct option is B.

8 0
4 years ago
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Vector A⃗ has magnitude 5.00 and is at an angle of 36.9∘ south of east. Vector B⃗ has magnitude 6.40 and is at an angle of 20.0∘
timama [110]

Answer:

3.9984i-3.0021j

Step-by-step explanation:

Due to the fact that we are only asked for the components on A, we will focus on that information.

The first thing we need to do is to dimension the magnitud of A as a hypotenuse of a right triangle. As the vector is ponting in south-east direction, we can asume that it´s (i) component will be positive and it´s (j) component will be negative.

Now, using trigonometric functions we can find the components of the vector A by multiplying the magnitude by -sin(x) for (j) and cos(x) for (i).

-5sin(36.9)=-3.0021

(this component is negative due to the fact that the vector is pointing down)

5cos(36.9)= 3.9984

Now we write in the correct notation x(i) + y(j)

3.9984i-3.0021j

8 0
4 years ago
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