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3 years ago

11

The formula for centripetal acceleration, a, is given below, where v is the velocity of the object and r is the object's distanc

e from the center of the circular path.

1 answer:

Ivahew [28]3 years ago

4 0

Answer:2/3-4

Step-by-step explanation:

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2 x ⅖<br> what is the answer

BartSMP [9]

4/5 is the sum of the answer. :)

5 0

2 years ago

Solve each system of equations (show steps) y=2x x+y=12

Hunter-Best [27]

Im learning this too right now hope this helps

1.you get y by itself and put what y equals where y is in the other equation
y=2x. x+y=12

x+2x=12
3x=12. (divided 3 on both sides)
x=4

2.after you find x(or y) put it in one of the problems above and solve for whats missing which in this case is y

y=2(4) 4+y=12
y=8. -4. -4
y=8

7 0

3 years ago

I need help 24 ten thousands equal to what

Allisa [31]

2,4000 is the answer

5 0

3 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

Read more at:

brainly.com/question/14320476

7 0

3 years ago

What is the relationship between force, mass, and acceleration?

zavuch27 [327]

Step-by-step explanation:

Force = Mass × Acceleration

SI Unit of Force Is Newton
SI Unit of Mass Is Kilograms
SI Unit of Acceleration Is Metre per second Square .

Hope it helps :)

6 0

3 years ago

Read 2 more answers