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Maslowich
3 years ago
13

$6.89 per pound for salmon OR $3.50 for 8 ounces (half a pound) of salmon

Mathematics
2 answers:
Blababa [14]3 years ago
7 0

Answer:

$6.89 pounds

Step-by-step explanation:

If half a pound is $3.50, then a pound of salmon is $7, and $6.89 pounds of salmon would be cheaper

garri49 [273]3 years ago
6 0

Answer: 3.50

Step-by-step explanation: Just answered this question

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Triangle ABC is translated using the rule (x, y) → (x + 2, y - 2). Which of the following describes the horizontal and vertical
BlackZzzverrR [31]
X controls the left and right movement of the point, while y controls the up and down.

x + 2 means that the new position of the point would be two spaces towards the right of the original point.

y - 2 means that the new position of the point would be two spaces lower than the original point.


Therefore, translate right 2 units, down 2 units, should be your answer


Hope this helps
3 0
3 years ago
You are collecting a sample of 60 data points from a population that you know to follow an exponential distribution. It is not a
11111nata11111 [884]

Answer:

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

For this case we have a large sample size n =60 >30

The exponential distribution is the probability distribution that describes the time between events in a Poisson process.

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

5 0
4 years ago
Techechtium-99m has a half-life of 6 hours. If 1000mg is in use, in how many hours will 62.5mg remain?
Nady [450]
One half life 1000 mg to 1000/2 =500 mg
One half life 500 mg to 500/2 = 250 mg
One half life 250 mg to 250/2 = 125 mg
Etc .......
7 0
3 years ago
Using the triangle below, what is Cos A?
Stells [14]

Answer:

a\b

Step-by-step explanation:

msgsewyjejjhensnsjmsgmyfydnansegnajtwmanae

6 0
3 years ago
Read 2 more answers
Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)
Marianna [84]

9514 1404 393

Answer:

   10·2^-8 grams

Step-by-step explanation:

The each day, the initial amount for that day is multiplied by 1/2. After 8 days, the initial amount has been multiplied by (1/2)^8, where the exponent of 8 signifies that (1/2) is a factor 8 times in the product.

After n days, the quantity remaining is ...

  q(n) = 10·(1/2)^n = 10·2^(-n)

after 8 days the remaining amount is ...

  q(8) = 10·2^-8 . . . grams

4 0
3 years ago
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