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3 years ago

Ram noticed three students used 1 2/10 dm of tape.what was the total used for three students???

Mathematics

1 answer:

OLga [1]3 years ago

7 0

Answer:

18/5

Step-by-step explanation:

From my understanding, this is 1 whole 2 upon 10

Step 1: Convert mixed fraction into fraction

Multiply whole number by denominator: 1 x 10 = 10

Add numerator: 10 + 2 = 12

Write the result as the numerator and use the same denominator.

12/10

Step 2: Find the total tape used

From my understanding, each student used 12/10 of the tap

So 3 students used: 12/10 x 3 = 18/5

Therefore, the total tape used for three students was 18/5.

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A six-sided number cube is rolled and a coin is tossed. What is the probability getting a 6 and a heads?

Whitepunk [10]

Cube= 1/6
coin= 1/2
1/2*3= 3/6
3/6+1/6= 4/6
4/6= 2/3
The answer is 4/6 or 2/3

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3 years ago

Read 2 more answers

Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t

likoan [24]

Hello from MrBillDoesMath!

Answer:

a(n) = -3n , n>= 1

Discussion:

a(1) = -3

a(2) = -6

a(3) = -9

a(4) = -12

The pattern looks like a(n) = -3n

Thank you,

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3 years ago

An education researcher claims that 58% of college students work year-round. In a random sample of 400 college students, 232

Hatshy [7]

Answer:

The proportion of college students who work year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58% of college students work year-round.

A random sample of 400 college students, 232 say they work year-round.

To test the researcher's claim use a one-proportion z-test.

The hypothesis can be defined as follows:

H₀: The proportion of college students who work year-round is 58%, i.e. p = 0.58.

Hₐ: The proportion of college students who work year-round is 58%, i.e. p ≠ 0.58. C

Compute the sample proportion as follows:

$\hat p=\frac{232}{400}=0.58$

Compute the test statistic value as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0$

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

$p-value=2\times P(z$

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work year-round is 58%.

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3 years ago

Your co-worker, Amanda, and you are reliving your high school athletic "glory days" during a coffee break. She played basketball

topjm [15]

Answer:

Our score = 0.60, Amanda's score = 0.25

Step-by-step explanation:

For Amanda

μ = 15 , σ = 4

z- score for X = 16 is (From z table)

z = (X - μ)/σ = (16 - 15)/4 = 0.25

For us

μ = 310 , σ = 25

z score for X = 325 (From z table)

z = (325-310)/25 = 0.60

Since our z score is better than Amanda's z score, we can say we did better

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3 years ago

A football coach wants to see how many laps his players can run in 15 minutes. During a non-mandatory meeting, the coach asks fo

mestny [16]

Answer:

Step-by-step explanation:

There are three reasons here why randomization is not being applied.

First, the coach is only observing football players attending the meeting. This is not representative of the entire team.

Second, there is no selection process. The coach isn't using a random generator or using a similar method.

Third, the players are volunteering for the test. The results will be biased because of this.

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3 years ago