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ivolga24 [154]
3 years ago
11

Find the perimeter of a rectangle whose length is (4a+b)cm and width (a+6)cm​

Mathematics
2 answers:
shusha [124]3 years ago
4 0

Answer:

P = 10a +2b+12

Step-by-step explanation:

P = 2 (l+w) for a rectangle

P = 2 ( 4a+b + a+6)

Combine like terms

P = 2(5a+b+6)

Distribute

P = 10a +2b+12

ArbitrLikvidat [17]3 years ago
4 0

Answer:

Given below

Hope it helps

Step-by-step explanation:

Perimeter= 2(l+b)

= 2(4a+b+a+6)

= 2(5a+b+6)

= 10a+2b+12 cm^2

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The daffodils flower Pate needs is 8, total number of flower when rose is 2, is 18 and the carnations to be needed for decoration is 15.

<h3>What is algebraic expression?</h3>

Algebraic expression are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Pete is making decorations for a dinner party. The instructions tell him to use 9 flowers for a medium-sized decoration which has 2 lilies, 1 rose, 3 carnations, 2 daffodils and 1 iris.

The ratio of daffodils to total flower is,

n=2/9.

To make a large decoration, Pete uses 36 flowers. Let suppose the daffodils flower he needs for this is x. Thus,

x=36*(2/9)

x=4*2

x=8

The rose flower is increased from 1 to 2. Thus, the total number of flower also be twice for decoration.

Flower=2*9

Flower=18

Now Pete uses 10 lilies instead of 2 which is 5 times the medium-sized decoration. Thus, the carnations to be needed is,

Carnations=3*5

Carnations=15

Hence, the daffodils flower Pate needs is 8, total number of flower when rose is 2, is 18 and the carnations to be needed for decoration is 15.

Learn more about the algebraic expression here;

brainly.com/question/2164351

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7 0
2 years ago
Factor. 16x^2+40x+25
rjkz [21]

Factor. 16x^2+40x+25

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<h2>(4x+5)^2</h2>

8 0
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Vaselesa [24]

Answer:

Step-by-step explanation:

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x=1.77777777778

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6 0
4 years ago
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Troyanec [42]

Answer:

No.

Step-by-step explanation:

The equation does not match the form of any conic section.

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

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