Given b equals -3, determine if it is a solution to 4b - 6 = - 18.
So, we have our given which is b = -3, and we are asked to determine if it a solution to the above equation.
To do this, we can plug -3 in for b and see if it works out.
Work:
Plug in -3 for b.
4(-3) - 6 = - 18
-12 - 6 = -18
-12 - 6 = - 18
Thus, b = -3 is a viable solution for the equation of 4b - 6 = -18.
Answer:
The highest score is 94.
Step-by-step explanation:
Let the highest score be denoted by, <em>A</em>, the lowest score be, <em>B</em> and the middle score be <em>X</em>.
Then,
A + X + B = 87 × 3 = 261 ...(i)
X + B = 83.5 × 2 = 167 ...(ii)
⇒ B = 167 - X ...(iii)
A + X = 89 × 2 = 178 ...(iv)
⇒ A = 178 - X ...(v)
Substitute (iii) and (v) in (i) and solve for <em>X</em> as follows:
A + X + B = 261
178 - X + X + 167 - X = 261
345 - X = 261
X = 84
Substitute the value of <em>X</em> in (iii) and solve for B as follows:
B = 167 - X
= 167 - 84
= 83
Substitute the value of <em>X</em> in (v) and solve for A as follows:
A = 178 - X
= 178 - 84
= 94
Thus, the highest score is 94.
Answer:
Yep.
Step-by-step explanation:
It's the equation of the circle of radius 4 units.
Answer:
y=4X+1 is the answer........
Answer:
The answer is "H [93%, 100%]"
Step-by-step explanation:
<em>I'll edit this in a second to show the process, but it may take a minute. Just have the answer for now.</em>
<em>This is a surprisingly useful question hah, I'll bet many will need to do this.</em>
This question is just finding the average. Pretty simple.
y = 86 + 82 + 91 + 98 + x / 5
y = 357 + x / 5
An easy way is to do the lowest question first, then go from lowest to second lowest and so on. Because if you go to the highest one and the answer is one of the lower ones, well, of course it's going to be within the 90-100 range, but that doesn't necessarily mean it's the answer.
y = 357 + (87) / 5
y = 444 / 5
y = 88.8
Okay, so the answer isn't G. Then let's try H.
y = 357 + (93) / 5
y = 450 / 5
y = 90
Yep, the answer is H. This is because it equals 90, which is indicative of the 90-100% range that Latoya needs to get an "A".