Don't you have the answer on their already
There are two costs involved:
1) the cost for lunch, which is given as a rate per student: $7.25/student
2) the cost for the trip which is $443.75 to be divided by the 25 students, so it is $443.75 / 25 = $17.75/student
Now, you can add up those two costs per student to have the total cost per student:
$7.25 + $17.75 = $25.00/student
Answer: $25.00
Answer:
Length = 3
Width = 7
Step-by-step explanation:
The perimeter is 20 feet
The area is 21 feet
Let x represent the length
Let y represent the width
20 = 2(x+y)
x+y= 20/2
x+y = 10.........equation 1
x × y= 21......equation 2
From equation 1
x= 10-y
Substitute 10-y for x in equation 2
(10-y)y= 21
10y - y^2 = 21
y^2 -10y + 21= 0
After factorization the result will be
(x-3)(y-7)
x-3= 0
x= 0+3
x= 3
y-7= 0
y= 0+7
y= 7
Hence the length is 3 and the width is 7
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Answer:
-12
Step-by-step explanation:
a(b - c)
b = 3, c = -3 and a = -2
-2( 3- -3)
-2(3+3)
-2(6)
-12
