Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that 
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So
You must survey 784 air passengers.
Using the expected value, it is found that the mean of the distribution equals $0.1.
- The expected value, which is the mean of the distribution, is given by <u>each outcome multiplied by it's probability</u>.
The probabilities of <u>each outcome</u> are:
- .0000001 probability of earning $1,000,000.
- .9999999 probability of earning $0.
Thus, the mean is given by:
Thus showing that the expected value is $0.1.
A similar problem is given at brainly.com/question/24855677
Answer:
1.25
Step-by-step explanation:
Because they are equal triangles, all of their sides are equal
so, lets take one side of each triangle (4, 5)
the law:
the scale factor = the larger side ÷ the smaller side
x = 5 ÷ 4
x = 1.25
For checking:
the larger side = the smaller side × the scale factor
Y = 4 × 1.25
Y = 5
Answer: 1.6 N/cm^2
Step-by-step explanation:
