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The general equation of a horizontal ellipse is
(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.
If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,
2b = 16
b = 8
b^2 = 64
The distance between the two foci is 2c. Thus,
2c = 12
c = 6
c^2 = 36
Then, a2 = 64 + 36 = 100. Substituting to the general equation:
x^2/100 + y^2/64 = 1
You would add them together if it’s on a number line bc u have to go 5 to get to 0 then another 13 so 13+5=18
You can answer this problem in two different ways: the first being (17 - 5) * x, and the second being 12 * x.
Answer:
1) The lateral area is LA=95 cm²
2) The surface area is SA=275 cm²
The answer is the option D) 95 cm² ; 275 cm²
Step-by-step explanation:
we know that
The surface area of the box (rectangular prism) is equal to
SA=2B+LA
where
B is the area of the base
LA is the lateral area of the box
<em>Find the lateral area</em>
LA=PH
where
P is the perimeter of the base
H is the height of the box
substitute
LA=2[15+6](2.26)=94.92 cm²
Round to the nearest whole number
LA=95 cm²
<em>Find the area of the base B</em>
B=(15)(6)=90 cm²
Find the surface area of the box
SA=2B+LA
substitute the values
SA=2(90)+95=275 cm²