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kari74 [83]
3 years ago
9

Please help! Please show all work! Thx!

Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

Part A)

86=2(x+22)

Part B)

l=26\text{ cm}

Step-by-step explanation:

We know that the rectangle has a length of (x+5) and a width of 12 cm.

Part A)

Remember the formula for the perimeter of a rectangle:

P=2(l+w)

We know that the perimeter is 86. Substitute that for P:

86=2(l+w)

Substitute (x+5) for the length l and 17 for w. So:

86=2((x+5)+17)

We can simplify this to acquire our equation:

86=2(x+22)

Part B)

To find the length, let's find our x first. We have the equation:

86=2(x+22)

Divide both sides by 2:

43=x+22

Now, subtract 22 from both sides. Therefore, our x is:

x=21

To find the length, remember that the length is:

l=x+5

Since we now know the value of x, substitute 21 for x:

l=21+5

Add:

l=26\text{ cm}

So, the length is 26 centimeters.

And we're done!

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2. Choose the graph that shows the solution of the inequality on the number line
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<u><em>Kavinsky</em></u>

4 0
2 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
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