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3 years ago

Please help meeeeee :///

Mathematics

2 answers:

eimsori [14]3 years ago

5 0

Wouldn't all the angles equal 180? We've been trying to learn these but I think so. Subtract both numbers by 180 and it should be the answer. Sorry if it's wrong but I'm not sure. I kinda hope this helps you any

xz_007 [3.2K]3 years ago

5 0

6) x=14+132
x=146
The measure angle x is 146°

7)74=38+x
-38 -38
36=x
Therefore the measure angle x us equal to 36°

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3(x + 1) = -2 (x - 1) -4

AlekseyPX

Answer:

x = -1

Step-by-step explanation:

use distribution

3x + 3 = -2x + 2 - 4

simplify

3x + 3 = -2x - 2

combine like terms

3x + 3 = -2x - 2

-3x -3x

3 = -5x - 2

+2 +2

5 = -5x

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3 years ago

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What is the area of a square that has a side length of 4x

Alex17521 [72]

A square with a side length of 4 would have an area of 16 because 4x4 equals 16.

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3 years ago

Can yall help me please?

eduard

Answer:

5/6 - 2/5 = 13/30

Step-by-step explanation:

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3 years ago

Find the arc length of the

Agata [3.3K]

Answer:

Circle circumference = radius * 2 * PI

Arc Length = radius * 2 * PI * Central Angle / 360 degrees

Arc Length = 7 * 2 * PI * (1/4)

= 3.5 * PI

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Step-by-step explanation:

4 0

3 years ago

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A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following

kiruha [24]

Answer:

After 47 days she will have more than 90 trillion pennies.

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

$1,2,4,8,16,32,.....$

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

$S_n=\dfrac{a(r^n-1)}{r-1}$

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

$\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}$

$\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}$

$\Rightarrow 90\times 10^{12}\le 2^n-1$

$\Rightarrow 2^n\ge 90\times 10^{12}+1$

$\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)$

$\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)$

$\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}$

$\Rightarrow n \ge 46.4$

$\Rightarrow n\approx 47$

8 0

3 years ago