Question

A fraction reduces to 36. If its denominator is 6x^5, what it's its numerator?

Answer 1

The answer is B because you will  cancel the x^5 part on top and bottom and the numerator left 6^3 and denominator left 6
6^3=216divid by 6 you will get 36

Answer 2

Answer:

Option (b) is correct.

Numerator is $N=6^3x^5$.

Step-by-step explanation:

Given : A fraction reduces to 36. If its denominator is $6x^5$.

We have to find the numerator.

Let numerator be N.

and denominator = $6x^5$.

Fraction (F) is numerator (N) over denominator(D).

$F=\frac{N}{D}$

Given : fraction is 36

$36=\frac{N}{6x^5}$

$6^2=\frac{N}{6x^5}$

Cross multiply , we get,

$(6^2)(6x^5)=N$

$N=6^3x^5$

Thus, numerator is $N=6^3x^5$.

Option (b) is correct.