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Iteru [2.4K]
3 years ago
13

Scale factor of quad STOP to quad RAIN____ pls answer I need this so baddd

Mathematics
2 answers:
Charra [1.4K]3 years ago
7 0

Answer:

The scale factor is 1/9

Step-by-step explanation:

99 × 1/9 = 11

nekit [7.7K]3 years ago
3 0
it has to be 148 because it’s part of the triangle
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Help me with this geometry question!!
vodka [1.7K]

Answer:

A) trapezoid a=141 b=69

Step-by-step explanation:

It must be a trapezoid because two of the sids are not parallel.  The interior angles of any quadrilateral must equal 360, and each side of a trapezoid  must equal 180, so:

A) trapezoid a=141 b=69

3 0
3 years ago
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ARE THESE CORRECT!! EXPLAIN IF UR RIGHT ILL MARK BRAINLIEST!!
Naddika [18.5K]

Answer:

the rhombus and square must be switched

Step-by-step explanation:

the square looks like a diamond because its tilted sideways

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3 years ago
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I will mark u as the brainiest if u get this correct<br> thx<br> x
miss Akunina [59]

Answer:first fine the perimeter 42cm then do the lenth then width and u get the answer

Step-by-step explanation:

or find it on google

5 0
3 years ago
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Use a surface integral to find the surface area of the portion of the sphere xUse a surface integral to find the surface area of t
brilliants [131]

Parameterize this surface (call it S) by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos v\,\vec k

with 0\le u\le2\pi and 0\le v\le\dfrac\pi4. The limits on u should be obvious. We find the upper limit for v by solving for v where the sphere and cone intersect:

\begin{cases}x^2+y^2+z^2=1\\z=\sqrt{x^2+y^2}\end{cases}\implies x^2+y^2=\dfrac12

\implies(\cos u\sin v)^2+(\sin u\sin v)^2=\dfrac12

\implies\sin^2v=\dfrac12

\implies\sin v=\dfrac1{\sqrt2}\implies v=\dfrac\pi4

Take the normal vector to S to be

\vec r_u\times\vec r_v=-\cos u\sin^2v\,\vec\imath-\sin u\sin^2v\,\vec\jmath-\cos v\sin v\,\vec k

(orientation does not matter here)

Then the area of S is

\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{\pi/4}\int_0^{2\pi}\sin v\,\mathrm du\,\mathrm dv

=\displaystyle2\pi\int_0^{\pi/4}\sin v\,\mathrm dv=\boxed{(2-\sqrt2)\pi}

4 0
3 years ago
14. In a month-long randomized comparative experiment, participants were
kobusy [5.1K]

Answer: A

Step-by-step explanation:

Confidence interval for the difference in the two proportions is written as

Difference in sample proportions ± margin of error

Sample proportion, p = x/n

Where x = number of success

n = number of samples

For the first treatment,

x = 35

n1 = 50

p1 = 35/50 = 0.7

For the second treatment,

x = 16

n2 = 40

p2 = 16/40 = 0.4

Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.005 = 0.995

The z score corresponding to the area on the z table is 2.576. Thus, the z score for 99% confidence level is 2.576

Margin of error = 2.576 × √[0.7(1 - 0.7)/50 + 0.4(1 - 0.4)/40]

= 2.576 × 0.10099504938

= 0.26

Confidence interval = 0.7 - 0.4 ± 0.26

= 0.3 ± 0.26

Option A is correct

4 0
4 years ago
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