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Nataliya [291]
3 years ago
10

In which instance will total revenues decline? Multiple Choice price increases and Ed equals -.41 price increases and demand is

unit-elastic price decreases and demand is elastic price increases and Ed equals -2.47
Business
1 answer:
liraira [26]3 years ago
8 0

Answer:

price increases and Ed equals -2.47

Explanation:

Elasticity of demand measures the responsiveness of quantity demanded to changes in price.

Demand is inelastic if a change in price has little or no effect on quantity demanded. The absolute value of the coefficient for inelastic demand is less than 1.

If price increases and demand is inelastic, total revenue would increase because there would-be little or no change in quantity demanded as a result of the price increase.

Demand is elastic if a small change in price has a greater effect on the quantity demanded.

The absolute value of the coefficient for elastic demand is greater than 1.

If demand is elastic and price is increased, revenue would fall because of the decease in quantity demanded.

If demand is elastic and price is deceased, revenue would rise because of the increase in Quanitity demanded as a result of the fall in price.

Demand is unit elastic if a change in price has the same proportional effect on quantity demanded. The absolute value of the coefficient for unit elastic demand is one.

I hope my answer helps you

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Answer: <em>Option (d) is correct.</em>

From the given options, the following must be met for a communication to be categorized as advertising:

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3 years ago
When interest is compounded continuously, the amount of money increases at a rate proportional to the amount S present at time t
liubo4ka [24]

Answer:

a) - r=5%: S=$ 5,136.10

- r=4%: S=$ 4,885.61

- r=3%: S=$ 4,647.34

b) - r=5%: t=14 years

- r=4%: t=17 years  [/tex]

- r=3%: t=23 years  [/tex]

c) The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

Explanation:

The rate of accumulation of money is

dS/dt=rS

To calculate the amount of money accumulted in a period, we have to rearrange and integrate:

\int dS/S=\int rdt=r \int dt\\\\ln(S)=C*r*t\\\\S=C*e^{rt}

When t=0, S=S₀ (the initial capital).

S=S_0=Ce^{r*0}=Ce^0=C\\\\C=S_0

Now we have the equation for the capital in function of time:

S=S_0e^{rt}

a) For an initial capital of $4000 and for a period of five years, the amount of capital accumulated for this interest rates is:

- r=5%: S=4000e^{0.05*5}=4000*e^{0.25}= 5,136.10

- r=4%: S=4000e^{0.04*5}=4000*e^{0.20}=  4,885.61

- r=3%: S=4000e^{0.03*5}=4000*e^{0.15}=   4,647.34

b) We can express this as

S=S_0e^{rt}\\\\2S_0=S_0e^{rt}\\\\2=e^{rt}\\\\ln(2)=rt\\\\t=ln(2)/r

- r=5%: t=ln(2)/0.05=14

- r=4%: t=ln(2)/0.04=17

- r=3%: t=ln(2)/0.03=  23

c) When the interest is compuonded quarterly, the anual period is divided by 4. In 5 years, there are 4*5=20 periods of capitalization. The annual rate r=0.0525 to calculate the interest is also divided by 4:

S = 4000 (1+(1/4)(0.0525))^{5*4}=4000(1.013125)^{20}\\\\S=4000*1.297958= 5,191.83

If compuonded continously, we have:

S=S_0e^{rt}=4000*e^{0.0525*5}=4000*1.3= 5,200.71

The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

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Answer:

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