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grandymaker [24]
3 years ago
14

In 6n + 8N is best described as​

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

6n + 8n would be described as a variable because its a letter.

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The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x) = x2, which of t
kherson [118]
If we want to stretch graph vertically we need to multiply function f(x) with a number greater than 1. By doing so we will for same difference of x get larger difference of F(x) which means function will be stretched. 

If we want to flipp over x axis function F(x) all we need to do is to multiply it by -1. Function will change its sign thus for same values of x we will get value of F(x) with oposite sign which means function will be flipped over x axis.

Looking at offered answers we can say that A and B arent answer because we didnt multiply function with number greater than 1.

Answer is C)  G(x) = -4x^2
4 0
4 years ago
Questão 1
Evgesh-ka [11]

cara de culo

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

4 0
4 years ago
What is the final transformation in the composition of transformations that maps pre-image GHJK to image G'H"J"K"? a translation
kramer

Answer:

B

Step-by-step explanation:

trust meee

5 0
3 years ago
Read 2 more answers
Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.
Vladimir [108]
\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt
\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k

Given \mathbf r(1)=\mathbf i+\mathbf j, we have

\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12

so that the particular solution is

\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k
8 0
3 years ago
What is the graph that represents the equation 0.4(x + 3) = (y - 6)²?
Tasya [4]

Answer:

Step-by-step explanation:

7 0
2 years ago
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