All categories

2 years ago

What is the graph that represents the equation 0.4(x + 3) = (y - 6)²?

Mathematics

1 answer:

Tasya [4]2 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

Expand the following.... please help

Evgesh-ka [11]

= (3/8) (16x + - 24)
=(3/8) (16x) +(3/8)(-24)
=6x - 9

4 0

3 years ago

Plz show work If 12% of a number is 24, what is the number? Thank You very much

artcher [175]

.12x=24
x=24(.12)
x=200

6 0

3 years ago

Read 2 more answers

Given that ∠CEA is a right angle and bisects ∠CEA, which statement must be true?

loris [4]

Given that ∠CEA is a right angle which has been bisected by BE, then:
∠CEB=∠BEA
thus each angle will be complementary to each other, hence the size will be:
90/2=45°
hence the correct statement.
m∠CEB = 45°

8 0

3 years ago

Read 2 more answers

Write a quadratic equation with the solutions x=-5+sqrt 13/2 , -5-sqrt 13 /2 HELP please

QveST [7]

Answer:

If we used the quadratic formula to solve the equation we can say:

-b = -5

b² - 4ac = 13

2a = 2

Solving the first and last equations we get b = 5 and a = 1. Substituting these values into the second equation we get:

25 - 4c = 13

Solving this we get c = 3 so the answer is x² + 5x + 3.

4 0

3 years ago

If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?

Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

20 * 20 * 20 * 20 * 20

First number 2nd number 3rd number 4th number 5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are $20^{5}$ ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

15 * 15 * 15 * 15 * 15

First number 2nd number 3rd number 4th number 5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are $15^{5}$

So the probability P can be calculate as:

$P=\frac{15^{5} }{20^{5} } \\P=0.2373$

Then the probability that their minimum is larger than 5 is 0.2373

7 0

3 years ago