Answer:
<em>-3/2 and 1</em>
Step-by-step explanation:
Given the arithmetic sequence (y+2) (y+3) and (2y²+1), the common difference is gotten by taking the difference in their terms. For example if we have 3 terms T1, T2, T3... the common difference d = T2-T1 = T3-T2
From the sequence given;
T1 = y+2, T2 = y+3 and T3 = 2y²+1
d = y+3-(y+2) = 2y²+1- (y+3)
open the parenthesis
y+3-y-2 = 2y²+1- y-3
1 = 2y²+1- y-3
1 = 2y²- y-2
2y²- y-2-1 = 0
2y²- y-3 =0
Factorize the resulting expression
2y²- y-3 =0
2y²- 2y+3y-3 =0
2y(y-1)+3(y-1) = 0
(2y+3)(y-1) = 0
2y+3 = 0 and y-1 = 0
2y = -3 and y =1
y = -3/2 and 1
<em>Hence the possible values of y are -3/2 and 1</em>
That is system of equation.
Answer:
Option 2
Step-by-step explanation:
it easy Add them all up and then you get 47/16 then divide them and convert it to mixed number and then you get 2 15/16
Answer:
208 
Step-by-step explanation:
We can find the area of the net by adding up the area of each of the 6 rectangles that make up the net. Since two of each rectangle are the same, we only have to find the area of the 3 different sized rectangles and multiply each by 2.
Rectangle pairs are:
- Left rectangle and right rectangle
- Top rectangle and the rectangle above the bottom rectangle
- Bottom rectangle and the rectangle surrounded by all for sides
Now, let's solve the question.
Left rectangle:
6 x 4 = 24, rectangle has area of 24 squared cm
Top rectangle:
6 x 8 = 48, rectangle has area of 48 squared cm
Bottom rectangle:
4 x 8 = 32, rectangle has area of 32 squared cm
Add up the areas:
(24 x 2) + (48 x 2) + (32 x 2) = 208
The rectangle has a surface area of 208 squared cm
Answer:
84x^10
Step-by-step explanation:
The coefficients multiply, and the exponents add.
(4x)( -3x^6)(-7x^3) = (4)(-3)(-7)x^(1+6+3) = 84x^10
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The rule for exponents is ...
(x^a)(x^b) = x^(a+b)
