Factor the four-term polynomial by grouping 3x-3+x^3-4x^2

Grant needs 2/3 cup of raisins and 3/4 cup of almonds to make trail mix, which statement can be used to find out if their are mo

deff fn [24]

To solve this problem, you must find a common denominator. First, you multiply the denominators together, then, multiply the numerator of the first fraction by the original denominator of the second fraction and vis-versa.

3*4 = denominator of both
2*4 = numerator of first fraction
3*3 = numerator of second fraction

Your fractions should end up being 8/12 cups of raisins and 9/12 cup of almonds. You can now compare these fractions.

Overall, there are 1/12 more almonds than raisins.

8 0

3 years ago

if workers were able to pave 1/3 of your driveway in 40 minutes if they work at same rate what portion of driveway will they pav

Dafna1 [17]

40min is 1/3
implies 20min is 1/6
60min is 1/3+1/6=3/6=1/2

5 0

3 years ago

(Round to the nearest tenth of a percent.) In 2011, the IRS increased the deductible mileage cost to

RUDIKE [14]

Answer:

$\%Change = 8.8\%$

Step-by-step explanation:

Given

$Initial = 51\ cents$

$Final = 55.5\ cents$

Required

Determine the percentage change

Percentage change is calculated as;

$\%Change = \frac{Final - Initial}{Initial} * 100\%$

$\%Change = \frac{55.5 - 51 }{51 } * 100\%$

$\%Change = \frac{4.5}{51} * 100\%$

$\%Change = \frac{4.5* 100\%}{51}$

$\%Change = \frac{450\%}{51}$

$\%Change = 8.8\%$

Hence, the percentage change is approximately 8.8%

6 0

2 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

6 0

2 years ago

Which type of data in an Enterprise System occasionally changes?

Otrada [13]

Answer:

the correct answer is master data

Step-by-step explanation:

Enterprise system is a information system which provides a company with a wide integration and coordination regarding the important business processes and also helps in providing seamless flow of information through out the company.

Master data is a type of data in the enterprise system which is changed only occasionally , as this data includes all the information related to the customers like name, contact etc which helps a firm in analyzing their behavior and conduct high level research.

5 0

3 years ago