Step-by-step explanation:
(a) dP/dt = kP (1 − P/L)
L is the carrying capacity (20 billion = 20,000 million).
Since P₀ is small compared to L, we can approximate the initial rate as:
(dP/dt)₀ ≈ kP₀
Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.
20 = k (6,100)
k = 1/305
dP/dt = 1/305 P (1 − (P/20,000))
(b) P(t) = 20,000 / (1 + Ce^(-t/305))
6,100 = 20,000 / (1 + C)
C = 2.279
P(t) = 20,000 / (1 + 2.279e^(-t/305))
P(10) = 20,000 / (1 + 2.279e^(-10/305))
P(10) = 6240 million
P(10) = 6.24 billion
This is less than the actual population of 6.9 billion.
(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))
P(100) = 7570 million = 7.57 billion
P(600) = 20,000 / (1 + 2.279e^(-600/305))
P(600) = 15170 million = 15.17 billion
Answer:
it will take 1.4 hours for the two trains to be 294 miles apart
Step-by-step explanation:
Let t be the time taken for each train
The westbound train travels at 95 miles per hour.
Speed of westbound train = 95
time = t
Distance = speed * time = 95 t
The eastbound train travels at 115 miles per hour
Speed of eastbound train = 115
time = t
Distance = speed * time = 115 t
both trains are 294 miles apart means the distance between both trains are 294 miles
So we add the distance of both trains and set it equal to 294
95t + 115t = 294
210 t =294
t = 1.4
So, it will take 1.4 hours for the two trains to be 294 miles apart
Answer:150
Step-by-step explanation:
The answer to the question is D
Using slope formula, the slope will be 1/6
