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KengaRu [80]
3 years ago
15

Expandir (x + 2y)^5

Mathematics
1 answer:
GrogVix [38]3 years ago
8 0
This is the concept of polynomial function, the question requires us to compute;
(x+2y)^5
=(x+2y)^2(x+2y)^2(x+2y)
=[(x^2+4xy+4y^2)(x^2+4xy+4y^2)](x+2y)
=[x^2(x^2+4xy+4y^2)++4xy(x^2+4xy+4y^2)+4y^2(x^2+4xy+4y^2)](x+2y)
=(x^4+8x^3y+24x^2y^2+32xy^3+16y^4)(x+2y)
=x(x^4+8x^3y+24x^2y^2+32xy^3+16y^4)+2y(x^4+8x^3y+24x^2y^2+32xy^3+16y^4)
=x^5+10x^4y+40x^3y^2+80x^3y^3+80xy^4+32y^5
the answer is:
=x^5+10x^4y+40x^3y^2+80x^3y^3+80xy^4+32y^5
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AveGali [126]

Answer:

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Step-by-step explanation:

Given

See attachment for closet

Required

Determine the number of boxes needed to fill the closet

First, we calculate the volume of the two section.

According to the attachment

The first section has the following dimension:

Width = 5ft

Length = 4ft

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The second has the following dimension:

Width = 3ft ---- see the last label at the top

Length = 2ft --- This is calculated by subtracting the length of the first section (4ft) from the total length of the closet (6ft) i.e. 6ft - 4ft

Height = 8ft

So: The volume of the closet is:

Volume = W_1 * L_1 * H_1 + W_2 * L_2 * H_2

Volume = 5ft * 4ft * 8ft + 3ft * 2ft * 8ft

Volume = 160ft^3 + 48ft^3

Volume = 208ft^3

The number of box needed is then calculated by dividing the volume of the closet (208ft^3) by the volume of each box (32ft^3)

Boxes = \frac{208ft^3}{32ft^3}

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7 0
3 years ago
What is 2.20 rounded to the nearest tenth?
Musya8 [376]
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Simplify the following expressions and remember to pay attention to the signs plz help me
ioda

2 negatives can be converted to a plus sign. -(-x) can be +x or just x.

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-54+23

<u>23-54=-31</u>

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Now let's pause fer a sec. When a negative is being divided by another negative, the quotient(answer to division problem) becomes a positive.

<u>-48/-6=8</u>

<u></u>

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---

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Answer:

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Klio2033 [76]

Answer:

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time must be in hours, hence

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8 0
3 years ago
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