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3 years ago

Factor the trinomial 6y squared + 19y + 15

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

1.y = -5/3 = -1.667

2. y = -3/2 = -1.500

Step-by-step explanation:

90 + -1 = -91

-45 + -2 = -47

-30 + -3 = -33

-18 + -5 = -23

-15 + -6 = -21

-10 + -9 = -19

-9 + -10 = -19

-6 + -15 = -21

-5 + -18 = -23

-3 + -30 = -33

-2 + -45 = -47

-1 + -90 = -91

1 + 90 = 91

2 + 45 = 47

3 + 30 = 33

5 + 18 = 23

6 + 15 = 21

9 + 10 = 19

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Answer:

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Step-by-step explanation:

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The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What

Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .