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koban [17]
3 years ago
14

Factor the trinomial 6y squared + 19y + 15

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

1.y = -5/3 = -1.667

2. y = -3/2 = -1.500

Step-by-step explanation:

90    +    -1    =    -91  

     -45    +    -2    =    -47  

     -30    +    -3    =    -33  

     -18    +    -5    =    -23  

     -15    +    -6    =    -21  

     -10    +    -9    =    -19  

     -9    +    -10    =    -19  

     -6    +    -15    =    -21  

     -5    +    -18    =    -23  

     -3    +    -30    =    -33  

     -2    +    -45    =    -47  

     -1    +    -90    =    -91  

     1    +    90    =    91  

     2    +    45    =    47  

     3    +    30    =    33  

     5    +    18    =    23  

     6    +    15    =    21  

     9    +    10    =    19

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Answer:

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Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

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=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

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3 years ago
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Answer:

the answers would be the same

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