A city council consists of seven Democrats and six Republicans. If a committee of five people is selected, find the probability

Question

3 years ago

8

of selecting two Democrats and three Republicans.

2 answers:

RSB [31] · Answer 1 · 2022-06-04T01:56:09+03:00

Answer:

solution,

let d and r denote democrats and republicans respectively.

given,

no. of total sample space n(s) =7+6=13

no. of total democrats n(d)=7

no. of total republicans n(r)=6

no. of democrats events n(D1)=2

no. of republicans events n(R1)=3

it is a mutually exclusive event. so the probability of selecting two democrats and three republicans= {n(D1)/n(s)} * {n(r1)/n(s)}

=(2/13)*(3/13)

=6/169

raketka [301] · Answer 2 · 2022-06-04T03:46:00+03:00

3 0

Answer:

6/169

Step-by-step explanation:

A city council consists of seven Democrats and six Republicans. If a committee of five people is​ selected, find the probability