The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
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Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
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<span>Part A: Area = length * width = (6x^2 + 3x - 2) * (x^3 - 2x + 5)
Multiply it out and simplify.
part B: </span><span>Take the first term 6x^2 and multiply each of the term x^3, -2x & 5. Then take 3x and multiply each of the term x^3, -2x & 5. Do the same with -2.
Then add like terms and simplify.</span>
Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
Y WILL BE 11 THATS ALL I KNOW
