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Bad White [126]
3 years ago
10

PLEASE I need help GeoMETRY

Mathematics
1 answer:
9966 [12]3 years ago
5 0

Answer:

2. 2.3

3.  37.2 m

Step-by-step explanation:

2.  tan theta = opposite/ adjacent

tan 25 = x/5

Multiply each side by 5

5 tan 25 = x/5 *5

5 tan 25 = x

2.331538291

To the nearest tenth

2.3 =x

3.  We want to find the height or y

sin theta = opposite/ hypotenuse

sin 60 = y /43

Multiply each side by 43

43 sin 60 = y/43 * 43

43 sin 60 = y

37.23909236 = y

To the nearest tenth

37.2 =y

The light pole is 37.2 meters tall

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Rufina [12.5K]
This is the concept of density, volume and mass of different materials; To calculate for the volume of an aluminium material with density of 2.375 grams per cubic centimeter and a mass of 0.78 Kilogram we proceed as follows;
Density=mass/volumemaking volume the subject we get;volume=mass/densitythus;mass=0.78 kg= 780 gdensity=2.375 g/cm^3Hence,volume=780/2.375=328.421 cm^3

4 0
3 years ago
given two terms in a geometric sequence find the 8th term and the recursive formula . a4=-12 and a5=-6
Crazy boy [7]

A geometric sequence is defined by a starting point, a, and a common ratio r

The first term is a, and you get every next term by multiplying the previous one by r.

So, our terms are

\left[\begin{array}{c|c}a_1&a\\a_2&ar\\a_3&ar^2\\a_4&ar^3=-12\\a_5&ar^4=-6\end{array}\right]

We can see that when we pass from a_4 to a_5 the number gets halved (-12 \mapsto -6)

This implies that the common ratio is r = \frac{1}{2}

So, the table becomes

\left[\begin{array}{c|c}a_1&a\\a_2&\frac{1}{2}a\\a_3&\frac{1}{4}a\\a_4&\frac{1}{8}a=-12\\a_5&\frac{1}{16}a=-6\end{array}\right]

So, we can derive the starting point from either a_4 or a_5:

\dfrac{1}{8}a = -12 \iff a = -12\cdot 8 = -96

The sequence is thus

\left[\begin{array}{c|c}a_1&-96\\a_2&-48\\a_3&-24\\a_4&-12\\a_5&-6\\a_6&-3\\\vdots&\vdots\end{array}\right]

And the recursive formula is

a_n = -\dfrac{96}{2^{n-1}}

7 0
4 years ago
The radius of a cylinder is 3.5 ft. The height is 14 ft. Find the surface area and volume of the cylinder to the nearest tenth o
ICE Princess25 [194]
Given:
radius : 3.5 ft
height : 14 ft

Surface Area of a cylinder = 2πrh + 2πr²
S.A. = 2 * 3.14 * 3.5ft * 14ft + 2 * 3.14 * (3.5ft)²
S.A. = 307.72ft² + 2 * 3.14 12.25ft²
S.A. = 307.72ft² + 76.93ft²
S.A. = 384.65 ft²  

Volume of a cylinder = πr²h
V = 3.14 * (3.5ft)² * 14ft
V = 3.14 * 12.25ft² * 14ft
V = 538.51 ft³
4 0
3 years ago
Find the value of x for which the lines I and m are parallel.
yulyashka [42]

Answer:

15

Step-by-step explanation:

5x+13+11x-73=180°( co-interior angles sum is 180)

5x+11x+13-73=180°

16x-60=180

16x=180+60

16x=240

x=15

5 0
2 years ago
When f(x)=-3, what is x?
Anna35 [415]

Answer:

Step-by-step explanation:

For example, if f(x)   =  2x   + 7

      then         f(-3) = 2(-3) + 7

                     f(-3) = 1

3 0
3 years ago
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