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4 years ago

15

A flagpole cast a shadow 16 feet long at the same time a pole 9 feet high casts a shadow 6feet long what is the height in feet o

f the flagpole

1 answer:

Doss [256]4 years ago

7 0

The pole would be 24 feet high.
X/16=9/6
X=24

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Divide. Will mark brainliest.

horrorfan [7]

Answer:

7t^5 - t^3

6x -3 +2x/y

Step-by-step explanation:

A. (7t^8 - t^6)/t^3

Separate into 2 fractions

(7t^8/t^3) - (t^6)/t^3

Remember a^b / a^c = a^ (b-c)

7 t^(8-3) - t^(6-3)

7t^5 - t^3

B (12x^2y - 6xy +4x^2)/2xy

Separate into 3 fractions

12x^2y/2xy - 6xy/2xy +4x^2/2xy

Remember a^b / a^c = a^ (b-c)

12/2 x^(2-1) y^(1-1) - 6/2 x/x * y/y +4/2 x^(2-1) /y

6 x y^0 -3*1*1 +2 x/y

Remember that x^0 = 1

6x -3 +2x/y

5 0

3 years ago

Can anyone help with these? I appreciate and I will award 5 stars and brainliest

nekit [7.7K]

<u>Graph 1</u>

coordinates : (0,-5) (-6,-2)

m = (y2-y1)/(x2-x1)

m = (-2-(-5))/(-6-0)

m = 3/-6 = -1/2

Substitute the values,

y = mx + c

-2 = (-1/2)(-6) + c

-2 = 3 + c

c = -5

Thus, equation is y = -1/2x -5

<u>Graph </u><u>2</u>

coordinates : ( 4,-2) (-5,3)

m = (y2-y1)/(x2-x1)

m = (3-(-2))/(-5-4)

m = 5/-9

Substitute the values,

y = mx + c

-2 = (-5/9)(4) + c

-2 = -20/9 + c

c = 2/9

Thus, the equation is y = -5/9 + (2/9)

Hope it helps :)

8 0

4 years ago

Find the area of the rhombus

MAXImum [283]

<h3> Solution :-</h3>

Area of rhombus :-

$\bf \star \: \: \boxed{ \bf \dfrac{d_{1}d_{2}}{2} }$

$\sf \longrightarrow d_{1} = 4 \sqrt{3} + 4 \sqrt{3} = 8 \sqrt{3}$

$\sf \longrightarrow d_{2} = 4 + 4 = 8$

Area of rhombus :-

$: \implies \sf \dfrac{8 \sqrt{3} \times 8 }{2}$

$: \implies \sf 8 \sqrt{3} \times 4$

$: \implies \bf 32 \sqrt{3} \: {m}^{2}$

6 0

3 years ago

Please help! I need this quickly

Lera25 [3.4K]

Answer:

x + 3y = 30

Step-by-step explanation:

We are given that a line contains the points (12,6) and (-3,11).

We want to write the equation of this line in standard form.

Standard form is written as ax+by=c, where a, b, and c are free integer coefficients, however a and b cannot be 0, and a cannot be negative.

Regardless, before we write an equation in slope-intercept form, we must first write the equation in a different form, such as slope-intercept form.

Slope-intercept form is given as y=mx+b, where m is the slope and b is the value of y at the y-intercept.

So first, let's find the slope of the line.
The slope (m) can be found using the formula $\frac{y_2-y_1}{x_2-x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points.

Even though we already have 2 points, let's label their values to avoid any confusion and mistakes when calculating.

$x_1=12\\y_1=6\\x_2=-3\\y_2=11$

Now substitute these values into the formula.

m= $\frac{y_2-y_1}{x_2-x_1}$

m= $\frac{11-6}{-3-12}$

Subtract

m= $\frac{5}{-15}$

Simplify

m= $-\frac{1}{3}$

The slope is -1/3

Here is the equation of the line so far in slope-intercept form:

$y=-\frac{1}{3} x + b$

We need to solve for b.

As the equation passes through (12,6) and (-3,11), we can use either one to help solve for b.

Taking (12, 6) for example:

$6=-\frac{1}{3}(12) + b$

Multiply

$6=-\frac{12}{3} + b$

Divide

6 = -4 + b

Add 4 to both sides.

10 = b

Substitute 10 as b in the equation.

$y = -\frac{1}{3} x + 10$

Here is the equation in slope-intercept form, but remember, we want it in standard form.

In standard form, the values of both x and y are on the same side, so let's add -1/3x to both sides.

$\frac{1}{3} x + y = 10$

Remember that a (the coefficient in front of x) has to be an integer, 1/3 is not an integer.

So, let's multiply both sides by 3 to clear the fraction.

$3(\frac{1}{3} x + y) = 3(10)$
Multiply.

<u>x + 3y = 30</u>

<u></u>

Topic: finding the equation of the line (standard form)

See more: brainly.com/question/27575555

4 0

2 years ago

PLZ HELP QUICK!!! - Fill in the missing values in the tables. If necessary, round your answer to three decimal places.

enot [183]

Answer:

first blank = 10 (for table 1)

second blank = 30 (for table 2)

====================================================

Explanation:

You could use a calculator to determine the value of b, then compute b^x for that first box. But as the instructions state, we don't need to use one. Why is that? Because the tables provide enough information to fill in the blanks.

Table 1 shows x = 2.096 lead to some unknown y value. Meanwhile, table 2 has x = 10 lead to y = 2.096; note the 2.096 shows up again. The exponential and log functions are inverses of each other. They undo each other's operation. This is similar to how division undoes multiplication, and vice versa.

Going in reverse of table 2, we will conclude that 10 must go in the blank for table 1. Therefore, b^x = 10 when x = 2.096

------------

Similarly, we will have 30 in the blank for table 2. Table 1 shows x = 3.096 lead to y = 30. Table 2 is the reverse of that as it is the inverse.

Throughout either section, we didn't need to find the value of b.

3 0

3 years ago