Answer:
None
Step-by-step explanation:
Simply solve each linear equation and get value of R.
Or another way can be to put value of R in all four options and find whether left hand side is equal to right hand side or not.
A) 
R = -14
B) 
R = -37/8
C) 
R = 22/3
D) 
R = -28
So, none of the option's are having solution R =-17.
There's lots of even functions, but two that come to mind are the absolute value function, IxI, and x^2. These are even because they are reflected over the y axis. Another way to find this is that (-x)^2 is equal to x^2 and so is I-xI, the algebraic method. Good luck!
Answer:
I'd say that is an "occupancy problem".
I ran a spreadsheet simulation of that and I'd say the probability is approximately .13
Those problems are rather complex to solve. What I think you would have to do is calculate the probability of
A) ZERO sixes appearing in 4 rolls.
B) exactly 1 six appears in 4 rolls.
C) exactly 2 sixes appear in 4 rolls.
D) exactly 3 sixes appear in 4 rolls. and
E) exactly 4 sixes appear in 4 rolls.
4 rolls of a die can produce 6^4 or 1,296 combinations.
A) is rather easy to calculate: The probability of NOT rolling a six in one roll is 5/6. In 4 rolls it would be (5/6)^4 = 0.4822530864
E) is fairly easy to calculate: The probability of rolling one six is (1/6). The probability of rolling 4 sixes is (1/6)^4 = 0.0007716049
Then we need to:
D) calculate how many ways can we place 3 objects into 4 bins
C) calculate how many ways can we place 2 objects into 4 bins
B) calculate how many ways can we place 1 objects into 4 bins
I don't know how to calculate D C and B
Step-by-step explanation:
The x-intercept of f(x) = (x + 6)(x - 3)
f(x) = 0 → (x + 6)(x - 3) = 0 → x + 6 =0 or x - 3 =0
x = -6 or x = 3
Therefore the x-intercepts are: (-6; 0) and (3; 0)
Your answer is (-6; 0)
The gradient of the function is constant s the independent variable (x) varies The graph passes through the origin. That is to say when x = 0, y = 0. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear. I believe the answer is C. Hope I helped!
