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wlad13 [49]
3 years ago
12

An expression to convert 50 miles per minute is?

Mathematics
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

the expression 50 miles per hour in miles per minutes is 0.83 miles per minutes

hope this helps

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What relation does not have an initial value of 50
Mamont248 [21]
I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

4 0
4 years ago
If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?
VARVARA [1.3K]

Answer:

k = 5

Step-by-step explanation:

Given y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 20 when x = 4, then

20 = 4k ( divide both sides by 4 )

5 = k

3 0
3 years ago
Read 2 more answers
A triangle flower bed has a perimeter of 15cm the drawing has a scale of 1:200. What is the perimeter of the actual flower bed
Natasha_Volkova [10]

Answer:

300cm

Step-by-step explanation:

scale 1:200 means 1cm on drawing represent 200cm on ground so 15cm will be 15×200 which is 3000cm

4 0
3 years ago
A bag of marbles contains 6 blue marbles, 2 yellow marbles, 4 red marbles, and 1 green marble. What is the probability of reachi
Mice21 [21]

Total marbles = 13

Number of yellow = 2


probability of getting yellow = 2/13

5 0
3 years ago
Last month Grace worked, and was paid for, a total of x hours. Some of the hours were on the day shift and the remainder of the
Salsk061 [2.6K]

Say her hourly pay was $p for the day shift and $1.2p for the night shift.

(1) x = 55. Clearly insufficient: we need to know how these 55 hours are split between the day shift hours and the night shift hour.

(2) Grace's gross pay for the hours she worked on day shift last month was exactly 50% of her total gross pay for last month. Not sufficient.

(1)+(2) Say Grace worked h hours on the day shift and 55-h hours on the night shift. Thus, her pay for the the hours she worked on day shift is $ph and the total gross pay is $ph+(55-h)*1.2p. From (2) we have that ph=0.5(ph+(55-h)*1.2p) --> reduce by p: h=0.5(h+(55-h)*1.2). We have 1 variable, so we can solve for it. Sufficient.

Answer: C.

7 0
3 years ago
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