Answer:
The amount one locust eats in a week is 420/30 = 14 grams so it eats 14/7 = 2 grams per day, therefore 21 locusts can eat 21 * 14 = 42 grams per day. 420 / 42 = 10 so the answer is 10 days or 1 week and 3 days.
We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.
The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.
The 95% confidence for the population mean will be:

Thus, the 95% confidence interval for the population mean will be (115,123)
So, option A is the correct answer
1 gallon = 16 cups
2 gallons = 16 x 2 = 32
32-10=22
there will be 22 cups left over
Are these 2 different questions or is this one equation
Answer:
10
Step-by-step explanation:
2* 5/6 = x/6
10/6 = x/6
Since the denominators are the same, the numerators are the same
x=10