Answer:
2
Step-by-step explanation:
hector(50)- lee(48)
2
Answer:
The index of refraction for Medium 2 would be 1.25
Step-by-step explanation:
We have the following data:
Speed of light in Medium 1 = V₁
Speed of light in Medium 2 = V₂
The speed of Light in Medium 2 is related to speed of light in Medium 1 as:
V₂ = 0.8 V₁
Moreover, it is given that Medium 1 is air with index of refraction equal to 1. i.e.
n₁ = 1
We need to find the index of refraction for medium 2. Lets name it is as n₂.
Snell's law related the above mentioned 4 quantities by following relation:
The ratio of indices of refraction of 2 mediums is equivalent to the reciprocal of ratio of phase velocities in those 2 mediums. Mathematically, this can be written as:

Substituting the values we have gives us:

This means, the index of refraction for Medium 2 would be 1.25
4.75=4+0.75
0.75=0.75/1=7.5/10=75/100=3/4
4 and 3/4
Answer:
no solutions
Step-by-step explanation:
n+(-n) = 3+ 15
n+-n = 0
0= 18
False
There are no solutions
Answer:
bae of 44 yds and a height of 28 yds
Step-by-step explanation:
11x7 = 88 yd^2 = area of small triangle
616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.
The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.
larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28