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REY [17]
3 years ago
15

Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

the plane region about the y-axis.
y = x3/2 y = 27 x = 0.

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

v=\pi(\frac{1392}{7} )

Step-by-step explanation:

kindly find attached to solved problem.

Given that

y= x^{2/3} \\\\y= 27\\\\x= 0

 

We can use the shell method as stated bellow

v= 2\pi\int\limits^d_c {p(y)} {h(y)}  dy  

we then proceed to substitute the given details into the shell formula and the solution for the volume was found to be

v=\pi(\frac{1392}{7} )

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Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a
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Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}

(a). Exactly one face up is red.

The odds of only the first die being red are:

P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}

The probability that all die turn up red is:

P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}

Thus, the probability that at least one die turns up red is:

P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}

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Step-by-step explanation:

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Take half of the middle term, 22, and square it.

So 11^2 = 121.

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