Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
The result can be shown in both exact and decimal forms.
Exact Form:
2
3
Decimal Form:
0.
¯
6
Hello!
First of all, we have a 4/52, or 1/13 chance of selecting a pair. Then, we select 1/3 cards 3 times, so we use this as our other fraction.
=
Therefore, we have a 1/39 or about 3%.
I hope this helps!
Answer:
Follows are the solution to the given question:
Step-by-step explanation:
There are missing details, which is why its solution is as follows:
When an angle bisector points so, its two sides of the corner are equidistant. Its corner bisector of a triangle angle is a straight line splitting its angle into two congruent directions. In such a single point, calling its incentives, follow three-angle engineers are required of its three triangle angles.
Answer:
so sorry ! but i need it
Step-by-step explanation:
