The given function : h(x) = 6 - x
We know that for any functions f(x) and g(x)
f*g (x)=f(x)\times g(x)
Therefore , h*h (x)=h(x)\times h(x)
h*h (x)=(6-x)(6-x)=(6-x)^2
h*h (x)=(6)^2-2(6)(x)+x^2 [ Using identity (a-b)^2=a^2+2ab+b^2 ]
h*h (x)=36-12(x)+x^2
\-------->\ h*h (x)=36-12(x)+x^2 Now, at x= 10 , we get
h*h (10)=36-12(10)+(10)^2
h*h (10)=36-120+100=36+100-120=136-120=16
Hence, the value of (h*h)(10) = 16
hoped it helped
Whenever you want to write the equation of a parallel line through some point (h, k), you can ...
- remove any added constant in the original given equation
- replace x with (x-h)
- replace y with (y-k)
- rearrange the resulting equation to the form required by the problem.
Using this formula here, we get
... 2(y +5) = 3(x -2)
Your answer form requires you solve this for y.
... 2y + 10 = 3x -6 . . . . . eliminate parentheses
... 2y = 3x -16 . . . . . . . . subtract the constant on the left (10)
... y = (3/2)x -8 . . . . . . divide by 2
Answer:
1. adjacent: ∠ACB and ∠BCD.
vertical: ∠ACB and ∠ECD
Step-by-step explanation:
Answer: Answers provided below in sequential order.
Step-by-step explanation: UV = 12(3)-1
(They said that x = 3)
UV = 35 (12*3-1)
70 = TV
TU = UV
8x + 11 = 12x - 1
-4x = 10
x = -10/4 or -5/2 (simplified)
TU = 8 (3) + 11
TU = 35 (24+11)
Answer:
y+4=–109(x-7)
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