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Vsevolod [243]
3 years ago
8

Simplify the expression.

a1" title=" \frac{4^{2} }{4^5} } " alt=" \frac{4^{2} }{4^5} } " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Illusion [34]3 years ago
8 0
4^{2-5}  =  4^{-3}  =  \frac{1}{ 4^{3} }
Hunter-Best [27]3 years ago
6 0
16/1024 hope this helps!!!!!
comment for a description
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This should equal 4 if I did this correctly.
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Answer:

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3 years ago
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Elodia [21]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We want to evaluate the following limit.


^{ \lim}_{n \to \infty} (1+\frac{1}{n})


We need to recall that, limit of a sum is the sum of the limit.


So we need to find each individual limit and add them up.

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}


Recall that, as n\rightarrow \infty,\frac{1}{n} \rightarrow 0 and the limit of a constant, gives the same constant value.



This implies that,


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5 0
3 years ago
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