Answer:
Fast train speed: 69 km/h
Slow train speed: 39 km/h
Step-by-step explanation:
Fast train:
-Time: 4.33
-Speed: x
-Distance: 4.33x
Slow train:
-Time: 7.66
-Speed: x - 30
-Distance: 7.66(x - 30)
7.66(x - 30) = 4.33x
7.66x - 229.8 = 4.33x
3.33x = 229.8
x = 69
If
, then
![\sqrt[2]{y}=\sqrt[2]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7By%7D%3D%5Csqrt%5B2%5D%7Bx%5E2%7D%3Dx)
if
, then
![\sqrt[3]{y}=\sqrt[3]{x^3}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%7D%3D%5Csqrt%5B3%5D%7Bx%5E3%7D%3Dx)
ok
so
![\sqrt[2]{64}=\sqrt[2]{8^2}=8](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B64%7D%3D%5Csqrt%5B2%5D%7B8%5E2%7D%3D8)
![\sqrt[3]{64}=\sqrt[3]{4^3}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5E3%7D%3D4)
well, the cube root usually bigger
Answer:
Area = (a² -5a) in²
Perimeter = (4a -10) in
Step-by-step explanation:
Let the length of the rectangle be a.
Given that, its width is 5 in less than the length.
So,
length ⇒ a
width ⇒ (a - 5)
First, let's find the area of the rectangle.
Area = length × width
Area = a ( a - 5 )
<em>Solve the brackets.</em>
Area = <u>(a² -5a) in²</u>
<u />
Now, let us find the perimeter of the rectangle.
Perimeter = 2 ( l + w )
Perimeter = 2 ( a + a - 5 )
Perimeter = 2 ( 2a - 5 )
Perimeter = <u>(4a -10) in</u>
It's the last one!
Hope this helps!
So in order to answer your question we calculate 40 - 22 wich gives us the answer of 18, so now we can say that 4/5 of apples weight 18 so now 18 / 4 = 4,5; 4,5 * 5 = 22,5 wich is the weight of apples you can put in the box, to know the answer we deduct the greatest weight of apples only from the weight of the box with those apples so, 40 - 22,5 = 17,5
so the answer to your question is 17,5
i hope i helped you
