H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
Answer:
Step-by-step explanation:
Factor the sum of cubes
a³ + b³ = (a+b)(a² - ab +b²)
= 2a² - 2ab + 2b²
a³ + b³ + 6ab = 2a² + 4ab + 2b²
= 2(a² + 2ab +b²)
= 2(a+b)²
= 8
The answer is -13.
Solution:
= |-4b - 8| + |-1 - b^2| + 2b^3
= |-4(-2) - 8| + |-1 - -2^2| + 2(-2)^3
= |8-8| + |-1+4| + 2(-8)
= |0| + |3| + (-16)
= -13
Answer:
c = 96°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
c is an exterior angle, thus
c = 50° + 46° = 96°
Out of 12 rolls the tail appeared 8 times
So this experimental probability =8/12 = 2/3 (answer c)