The probability that a player will be asked a math question and then a music question is 0.03125
<h3>How to determine the probability?</h3>
The size of the sections are given as:
Music = 0.5
Sport = 0.5
Others = 1
So, the total size is:
Total = 0.5 + 0.5 + 1 + 1 + 1
Evaluate
Total = 4
The probability of asking a math question is:
P(Math) = 1/4 = 0.25
The probability of asking a music question is:
P(Music) = 0.5/4 = 0.125
The required probability is:
P(Math and Music) = P(Math) * P(Music)
This gives
P(Math and Music) = 0.25 * 0.125
Evaluate
P(Math and Music) = 0.03125
Hence, the probability that a player will be asked a math question and then a music question is 0.03125
Read more about probability at:
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Answer:o
Step-by-step explanation:
Answer:
12 x 2+23 x −24=0. Enter an equation ... The first term is, 12x2 its coefficient is 12 . ... B ± √ B2-4AC x = ———————— 2A In our case, A = 12. B = 23. C = -24
Step-by-step explanation:
12 x 2+23 x −24=0. Enter an equation ... The first term is, 12x2 its coefficient is 12 . ... B ± √ B2-4AC x = ———————— 2A In our case, A = 12. B = 23. C = -24
Answer:
5 31/ 30 or 6 1/30
Step-by-step explanation:
I wish this helped you
With the mean and range, we can estimate the weights of the smallest and largest animals in each group.
For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]
<h3>
Which conclusions can be made with the given information?</h3>
We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.
- From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
- And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg
(Assuming a normal distribution).
Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:
- The largest dog weights 32kg + 45kg/2 = 54.5kg
- The smallest dog weights 32kg - 45kg/2 = 9.5kg
(again, assuming a normal distribution).
If you want to learn more about means and ranges:
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