Answer:
Step-by-step explanation:
d = dimes and a = quarters
0.10d + 0.25a > = 3 (thats greater then or equal) <===
For this case we have the following function:
F (x) = 3x ^ 2 + 6x-24
We observe that it is a quadratic equation.
The graph is therefore a parabola.
Its cut points are:
(-4, 0)
(2, 0)
Answer:
See attached image to see graph of the function
Answer:
x-coordinate = 0
Step-by-step explanation:
(-10,1) , (5,-5)
m = (y₂ - y₁)/(x₂ - x₁) = ( -5 - 1 ) / ( 5 - [-10] )
= -6 / ( 5 + 10)
= -6/15 = -2/5
y - y₁ = m (x - x₁)
y - 1 = (-2/5) ( x - [-10] )
y - 1 = (-2/5) ( x + 10 )
5 * (y -1) = -2 (x + 10)
5y - 5 = -2x -20
2x + 20 + 5y -5 = 0
2x + 5y + 15 = 0
Another point (a, -3) in on this line
2 * a + 5 * (-3) = -15
2a -15 = -15
2a = -15 +15
2a = 0
a = 0
x-coordinate = 0
In Δ ABC, ∠A=120°, AB=AC=1
To draw a circumscribed circle Draw perpendicular bisectors of any of two sides.The point where these bisectors meet is the center of the circle.Mark the center as O.
Then join OA, OB, and OC.
Taking any one OA,OB and OC as radius draw the circumcircle.
Now, from O Draw OM⊥AB and ON⊥AC.
As chord AB and AC are equal,So OM and ON will also be equal.
The reason being that equal chords are equidistant from the center.
AM=MB=1/2 and AN=NC=1/2 [ perpendicular from the center to the chord bisects the chord.]
In Δ OMA and ΔONA
OM=ON [proved above]
OA is common.
MA=NA=1/2 [proved above]
ΔOMA≅ ONA [SSS]
∴ ∠OAN =∠OAM=60° [ CPCT]
In Δ OAN


OA=1
∴ OA=OB=OC=1, which is the radius of given Circumscribed circle.
Answer:
I'll leave my comment here to give your post an up