Answer:
Surface area of square pyramid is computed as follows:
A = a² + a*√(a² + 4h²)
where <em>a</em> is the base length and <em>h</em> is the height.
If a model of the square pyramid is scaled down by a factor of x, then the surface area will be:
A' = (a/x)² + (a/x)*√[(a/x)² + 4(h/x)²]
A' = a²/x² + a/x * √[a²/x² + 4h²/x²]
A' = a²/x² + a/x * √[(a² + 4h²)/x²]
A' = a²/x² + a/x * √(a² + 4h²)/√x²
A' = a²/x² + a/x² * √(a² + 4h²)
A' = 1/x² * [a² + a*√(a² + 4h²)]
A' = 1/x² * A
That is, the surface area will be 1/x² times the original surface area. If h = 25 ft and a = 15 ft:
A = 15² + 15*√(15² + 4(25)²) = 1008.02 ft²
The factor is not mentioned in the question, nevertheless, the area will be 1008.02/factor² ft²
Given:
To find:
The value of 
.
Solution:
We have,
![[\because d(t)=80t]](https://tex.z-dn.net/?f=%5B%5Cbecause%20d%28t%29%3D80t%5D)
Now,
![[\because C(d)=0.09d]](https://tex.z-dn.net/?f=%5B%5Cbecause%20C%28d%29%3D0.09d%5D)
Therefore, the value of is 72.
Ur math teacher tweaked lol
Answer:
The graph g(x) is the graph f(x) vertically stretched by a factor of 7.
Step-by-step explanation:
Quadratic Equation: f(x) = a(bx - h)² + k
Since we are modifying the variable <em>a</em>, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.
