Answer:
Part 1) Helen will need 38 feet of fencing
Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet
Part 3) The approximate distance around half of the circle is 11 feet
Step-by-step explanation:
Part 1) How much fencing will Helen need?
Find out the perimeter
we know that
The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle
so
we have
substitute
therefore
Helen will need 38 feet of fencing
Part 2) What is the perimeter around the three sides of the rectangular section of the garden?
we have
substitute
therefore
The perimeter around the three sides of the rectangular section of the garden is 27 feet
Part 3) What is the approximate distance around half of the circle?
Find the circumference of semicircle
we have
substitute
therefore
The approximate distance around half of the circle is 11 feet
1. Using c=2pi(r), plug in 7 for r and solve. Then using a=pi(r)^2, plug in 7 for r once again and solve.
2. First, the diameter (d) is 12 so to get the radius (r), divide 12 by 2 and you should get 6. Then use c=2pi(r) for circumference and a=pi(r)^2 for area to solve.
3. To get the area of the semicircle, divide 16 by 2 to get the radius (r), plug it into a=pi(r)^2, and divide the answer you get for a by 2. To get the area of the triangle, use a=1/2bh, plugging in 16 for b and 10 for h. Finally, add your two answers (the a's from the semicircle and triangle problems).
4. Multiply 20 by 5.5 to get the area of the triangle. Then multiply 4.5 by 20 to get the area of the parallelogram and add your two quotients.
5. Use a=1/2bh and plug in 4 for b and 3 for h and solve. Then multiply the quotient by 10 and there's your volume. To find the surface area, solve SA=(10×4)+(10×3)+(10×5)+12. All I did there was find the area of all the sides and added them together.
6. To find the triangle's volume, use a=1/2bh (b=4, h=1.5) and then multiply the quotient of that by 2.5. To find the rectangle's volume, use v=lwh (l=4, w=2.5, h=2) and solve. Finally, add the triangle's volume and the rectangle's volume to get the total volume. To get its surface area, start with the rectangle. Find the areas of all the sides and add them together but then subtract the 2.5×4 rectangle as it is not on the surface. It should look like this: SA=2(4×2)+2(2.5×2)+10. Again, all I did was find the areas of all the rectangle's sides on the surface and added them. Next, find the triangle's areas on the surface and it should look like this: SA=2(1.5×4)+2(2.5×2.5). Finally, add both values of SA from the triangle and rectangle and there's your surface area.
Answer:
False
Step-by-step explanation:
If we were to flip the solid on the left so its parallel to the solid on the right, we would be able to compare the two more easier.
We can see that the right solid has dimensions of:
L = 1 cm
W = 3 cm
H = 5 cm
The left solid has dimensions of:
L = 1
W = 2
H = 7
If we were to add these all up, they would not equal.
R: 1 + 3 + 5 = 9
L: 1 + 2 + 7 = 10
