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zlopas [31]
3 years ago
13

triangle ABC has vertices A (0,1),B(2,5), and C (6,3). Triangle A'B'C' is created by reflecting triangle ABC over the y-axis. wh

at is the x-coordinate of vertex C'?
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
6 0
The x coordinate for c' is -6. When a point is reflected over the y axis, the positives and negatives switch for the x value.

I hope this Helps!
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A statue is mounted on top of a 16 foot hill. From the base of the hill to where you are standing is 77 feet and the statue subt
DanielleElmas [232]

Consider right triangle with vertices B - base of the hill, S - top of the statue and Y - you. In this triangle angle B is right and angle Y is 13.2°. If h is a height of the statue, then the legs YB and BS have lengths 77 ft and 16+h ft.

You have lengths of two legs and measure of one acute angle, then you can use tangent to find h:

\tan 13.2^{\circ}=\dfrac{\text{opposite leg}}{\text{adjacent leg}} =\dfrac{16+h}{77}, \\ \\ 0.2345=\dfrac{16+h}{77},\\  \\ 16+h=0.2345\cdot 77=18.0565,\\ h=18.0565-16=2.0565 ft.

Answer: the height of the statue is 2.0565 ft.

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Rick made a paper football that was 1 1/6 inches long Carly made one that was 5/6 inches long how many longer was Rick's paper f
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The riding stables just received an unexpected rush of registrations for the next horse show, and quickly needs to create some a
liraira [26]

Answer:

Maximum added area will be 60,000 ft²

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

Step-by-step explanation:

Consider the provided information.

There is sufficient funding to rent 1200 feet of temporary chain-link fencing.

The plan is to form two paddocks with one shared fence running down the middle.

The total length of fencing is 1200 feet that is same as the total perimeter including that shared line down the middle.

Therefore, the perimeter is

P = 1200 = 2L + 3w

Solve for L

1200-3w = 2L

L=600-\frac{3w}{2}

As we know the area of rectangle is A=L×W

Substitute the value of L in above formula.

A=(600-\frac{3w}{2})\times w\\A=600w-\frac{3w^2}{2}

A=-\frac{3w^2}{2}+600w

The above equation makes a downward parabola.

In order to find the maximum, find the vertex of parabola as shown:

W=\frac{-b}{2a}=\frac{600}{2\times\frac{3}{2}}=200

Hence, the width should be 200 ft in order to get maximum area,

Therefore, the length will be:

1200 = 2L + 3(200)

L=300

Now substitute the value of L and W in area formula.

A=300×200=60,000

Hence, maximum added area will be 60,000 ft²

Hence, the length should be 300 ft, and each paddock should then be 150 feet long.

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

5 0
4 years ago
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