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PtichkaEL [24]
2 years ago
11

Terry has a cube numbered from 1 to 6. He tosses the cube onto the floor 120 times. How many times should he expect it to land o

n a 2 or 3?
Mathematics
1 answer:
Temka [501]2 years ago
7 0

The expected value of a dataset is the mean or average of the dataset.

The cube is expected to land on a 2 or 3 a total of 40 times

The cube is said to be numbered from 1 to 6.

This means that, the probability of getting each number is 1/6.

So, the probability that the outcome is 2 or 3 is:

P(2\ or\ 3) = P(2) + P(3)

This gives

P(2\ or\ 3) = \frac 16 + \frac 16

Add fractions

P(2\ or\ 3) = \frac {1+1}6

P(2\ or\ 3) = \frac 26

Simplify

P(2\ or\ 3) = \frac 13

The number of rolls (n) is 120.

So, the expected value is:

E(x) = np

This gives

E(x) = 120 \times \frac 13

E(x) = 40

Hence, the cube is expected to land on a 2 or 3 a total of 40 times

Read more about expected values at:

brainly.com/question/13005177

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Answer: (24,-9)

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Step-by-step explanation:

3x + 4y = 36

Using (3,-2) will be:

= 3(3) + 4(-2)

= 9 - 8 = 1

Using (1,7) will be

= 3(1) + 4(7)

= 3 + 28 = 31

Using (0,0) equals to 0

Using (24,-9) will be:

= 3(24) +4( -9)

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Using (0,9) will be:

= 3(0) + 4(9)

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Using (4,6) will be:

3(4) + 4(6)

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Using (-12,18) will be:

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The correct options are (24,-9), (0,9 and (4,6)

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3 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

a. 8 gallons

b. (11-0.75t) gallons

Step-by-step explanation:

a. Here in this question, we are told that the total amount of fuel in the fuel tank is 11 gallons and the car consumes 0.75 gallon per hour. We are interested in knowing the amount of fuel left in the tank after driving for four hours.

We proceed as follows;

Since 0.75 gallon is consumed in an hour, the amount of fuel consumed in 4 hours would be the amount consumed in an hour * 4 hours

Mathematically, that would be 0.75 * 4 = 3 gallon

Now, the amount of fuel left is simply the difference between the initial amount of fuel in the tank minus the amount of fuel present after 4 hours.

That would be; 11 - 3 = 8 gallons

b. Like above, we want to know the amount of fuel left after t hours.

Since 0.75 is used up per hour, the amount used up in t hours would be 0.75 * t = 0.75t

Now, the amount of fuel that would be left in the tank would be the difference between what we had initially and what was used up.

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Step-by-step explanation:

1/3πr^2h

{(1/3)×(22/7)×2^2×6}m^3

[(1/3)×(22/7)×4×6)}m^3

{528/21}m^3

=25.1 m^3

NOTE:r=diameter divided by 2

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Answer:

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