Answer: 41.86 miles/hour
Step-by-step explanation:
Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [<em>in brackets</em>].
MPH MILES HOURS
50 20 [<em>0.4]</em>
[<em>40</em>] <u>70</u> <u>1.75</u>
Totals 90 miles 2.15 hours
Average = 90 miles/2.15 hours
41.86 mph
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Not sure if the 2 at the end is part of it all because with it the GCF can only be 1
but,
the GCF of 24a, 3b and 36ab is 3.
Answer:
Third option is correct: 1 / (t+4)^2
Step-by-step explanation:
This equation can be written as the following:
(t+3)/(t+4)*(1/t^2+7t+12)
We know this because of the division of fractions. For example:
(1/y)/(1/x) = (1/y)*(x/1)
Now that we know this, we can advance.
Now we have to try to factor (t^2+7t+12)
We can make this into (t+3)(t+4)
Ah! Perfect! There is a t+3 in the denominator of the first fraction!
We can now cancel these out.
Now our equation looks like this:
(1 / t+4) * (1 / t+4)
This can also be written as 1^2 / (t+4)^2 = 1 / (t+4) ^2
So the correct option is the third one.
Y = 32.25 x + 40
If it takes 6 hours to repair a car:
y = 32.25 * 6 + 40 = 193.5 + 40 = $233.50
The closest are $251.50 and $211.50.
$251.50 - $233.50 = $18
$233.50 - $211.50 = $22
$18 < $22
Answer:
The closest estimate is A ) $251.50