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3 years ago

Please help me i'll mark Brainliest!!!

Mathematics

1 answer:

ololo11 [35]3 years ago

5 0

4^(1/7) = ⁷√(4)

4^(7/2) = √(4)^7

7^(1/4) = ⁴√(7)

7^(1/2) = √(7)

I believe this is it...

Correct me if i'm wrong...

Hope this helps....

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Find the general solution of the following equation: y'(t) = 3y -5

Anton [14]

Answer:

The general solution of the equation is y = $\frac{A}{3}e^{3t}$ + 5

Step-by-step explanation:

Since the differential equation is given as y'(t) = 3y -5

The differential equation is re-written as

dy/dt = 3y - 5

separating the variables, we have

dy/(3y - 5) = dt

integrating both sides, we have

∫dy/(3y - 5) = ∫dt

∫3dy/[3(3y - 5)] = ∫dt

(1/3)∫3dy/(3y - 5) = ∫dt

(1/3)㏑(3y - 5) = t + C

㏑(3y - 5) = 3t + 3C

taking exponents of both sides, we have

exp[㏑(3y - 5)] = exp(3t + 3C)

3y - 5 = $e^{3t}e^{3C}$

3y - 5 = $Ae^{3t}$ $A = e^{3C}$

3y = $Ae^{3t}$ + 5

dividing through by 3, we have

y = $\frac{A}{3}e^{3t}$ + 5

So, the general solution of the equation is y = $\frac{A}{3}e^{3t}$ + 5

3 0

4 years ago

Simplify: (8t4 + 6 )+(914 – 2ť + 6t? – 6 )

vekshin1

Answer:t

2⋅(17t 2 −2t+6)

Step-by-step explanation:

v(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

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Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

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6.1 Pull out like factors :

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disa [49]

Answer:

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ikadub [295]

Answer:

x=3 and x=-5

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To find the x intercepts set y =0 and solve for x

0 = x^2+2x-15

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5+-3 =2

0 = (x+5) (x-3)

Using the zero product property

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