What is the solution of the linear-quadratic system of equations? {y=x^2+5x−3 {y-x=2

Mathematics

1 answer:

Rina8888 [55]3 years ago

3 0

Answer: the above stated equation is a quadratic equation

Step-by-step explanation:

Given the following equations

y = x^2 + 5x - 3....equation 1

y-x = 2

y = x + 2........equation 2

Let equation 1 equal equation 2

x^2 + 5x -3 = x + 2

Bringing the equation to one side and equating to zero

X^2 +5x - 3 -x -2 = 0

X2 + 5x -x -3 -2 = 0

X^2 + 4x -5

Solving the aquatic equation

(x + 5)(x -1) = 0

X + 5 = 0

X1 = -5

X- 1 = 0

X2 = 1

To prove:

Substitute the values for x1and x2 into the equation x^2 + 4x - 5 = 0

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weqwewe [10]

Answer:

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Have a good day :)

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2 years ago

By selling a stool for rupees 67.50,a carpenter loses 10%.how much percent would he gain or lose by selling it for rupees 82.50.

valentina_108 [34]

Let the actual value of the stool be x.

So if the carpenter sells the stool x rupees he neither loses, now wins anything.

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So using the same method:

82.50=75+y%*75

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Answer: 10% gain.

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finlep [7]

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