In circle N, KL ≅ ML. What is the measure of ?

Mathematics

2 answers:

viva [34]3 years ago

8 0

Answer:

The answer is 132 degrees

Step-by-step explanation:

Just took the test and go it right ✔

pentagon [3]3 years ago

3 0

This is the concept of geometry, for us to get the value of JM we will requires to get the value of x first;
From the diagram we have been told that;
KL=ML
KL=7x+7
ML=8x-3
thus;
8x-3=7x+7
collecting the like terms we get;
8x-7x=7+3
x=10
But, JM=13x+2
substituting the value of x in JM we get:
JM=13(10)+2
JM=130+2
JM=132
The answer is 132°

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Dimas [21]

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I hope this helps!

6 0

3 years ago

Read 2 more answers

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$