Answer:
what is this mean is there a question
X2+y2–x–2y–11/4=x2−x+14−14+y2−2y+4−4−11/4=(x−12)2+(y−2)2−14−4−114=(x−12)2+(y−2)2−7=0(x−12)2+(y−2)2=(7√)2
Center(1/2 ,2)
radius = \sqrt 7
1+8=9
9*40=360
--------------------------------
1:8=40:320
Hey there!
The excluded factors of an equation are the values of x in which the result is undefined. This means, if the denominator or x(x-3) is equal to 0, then your solution would be undefined.
To find these values, set up this equation and solve for the possible values of x:
x(x-3)=0
To solve for one of the values, divide both sides by (x-3):
x(x-3)/(x-3)=0(x-3)
Because (x-3) would cancel on the left hand side of the equation, and on the right hand side, anything divided by 0 is 0, you should get:
x=0
Now that you have one of the excluded values, solve for the other:
First divide both sides by x:
x(x-3)=0
x-3=0
Finally, add -3 to both sides to get:
x=3
Therefore, your excluded values of x would be 0 and 3.
Hope this helps and have a wonderful day! :)
The answer to tour question is
24 1/6
