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STALIN [3.7K]
3 years ago
8

Simplify the rational expression. (Your final answer should have one term.)

Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

\frac{73}{36}

Step-by-step explanation:

\frac{3}{4} - \frac{2}{9} + \frac{3}{2}

1. Convert all the fractions to a common denominator.

For this problem, the common denominator will be 36

\frac{3}{4} * 9 = \frac{27}{36}

\frac{2}{9} * 4 = \frac{8}{36}

\frac{3}{2} * 18 = \frac{54}{36}

2. Substitute the values back into the equation, and solve

\frac{3}{4} - \frac{2}{9} + \frac{3}{2}

= \frac{27}{36} - \frac{8}{36} + \frac{54}{36}

= \frac{19}{36} + \frac{54}{36}

= \frac{73}{36}

andrezito [222]3 years ago
3 0

Answer:

  • 2 1/36

Step-by-step explanation:

  • 3/4 - 2/9 + 3/2 =
  • 3/4*9/9 - 2/9*4/4 + 3/2*18/18 =   ⇒ Common denominator LCM(4,9,2)=36
  • 27/36 - 8/36 + 54/36 =
  • (27 - 8 + 54)/36 =
  • 73/36 =
  • 2 1/36
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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


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