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kozerog [31]
3 years ago
5

Evaluate the function f(x) = 6x - 5 at f(1)

Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0
Remove the parentheses around the expression 1
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-10.0-(-3.4)<br><br> also you have to simplify your answer
uysha [10]
-13.4 is the answer. And this is simplified form
4 0
3 years ago
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Extra points help me please
podryga [215]

Answer:

b

Step-by-step explanation:

5 0
2 years ago
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Brandon is playing hide-and-seek with Katy and Tony. Katy is hiding 63 feet south of Brandon, and Tony is hiding due east of Kat
sergij07 [2.7K]

Answer:

60 feets

Step-by-step explanation:

Given that :

Using Pythagoras rule :

Hypotenus = sqrt(Adjacent^2 + opposite^2)

From the attached picture :

x² = 87^2 - 63^2

x^2 = 7569 - 3969

X^2 = 3600

Take the square root of both sides :

X = sqrt(3600)

X = 60 feets

Hence, Katy and Tony are 60 feets apart

6 0
2 years ago
Please help me!
Tamiku [17]
Check the picture below.

notice the sides, now, on the second triangle, side 6 slants a bit more to fit in 13, on the third triangle, side 6 slants even further to fit 13 in, now, if 6 were to slant completely, it'll make a flat-line with side 5, and there will be a triangle no more.

but even if side 6 would stretch to a flat-line, 5+6 is just 11, whilst side 13 is longer than that, so no dice.

4 0
3 years ago
United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res
Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so n = 200.

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So \pi = 0.0995.

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find P(X < 18), with \pi = 0.0995, n = 200. We can use a binomial probability calculator, and we find that:

P(X < 18) = 0.2927.

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0
2 years ago
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